What is the asymptotes of f(x)=(x+9)/(x^2-x-42) ?

The asymptotes of f(x)=(x+9)/(x^2-x-42) is Vertical: x=-6,x=7,Horizontal: y=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

asymptotes of f(x)=(x+9)/(x^2-x-42)

asymptotes

f (x) = \frac{x + 9}{x ^{2} - x - 42}

Vertical : x = - 6, x = 7, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{x + 9}{x ^{2} - x - 42} : x = - 6, x = 7

Horizontal Asymptotes of

\frac{x + 9}{x ^{2} - x - 42} : y = 0

Slant Asymptotes of

\frac{x + 9}{x ^{2} - x - 42} :

None

Vertical : x = - 6, x = 7, Horizontal : y = 0

f (x) = \frac{x ^{2} + 4}{x ^{2} - 25}

f (x) = \frac{x ^{2} - 16}{x ^{2} + 16}

f (x) = x - arctan (x)

\frac{2 x + 10}{x ^{2} + 9 x + 20}

f (x) = 2^{- x} + 6

What is the asymptotes of f(x)=(x+9)/(x^2-x-42) ?
The asymptotes of f(x)=(x+9)/(x^2-x-42) is Vertical: x=-6,x=7,Horizontal: y=0