What is the asymptotes of f(x)=((x^2-9))/(2x+4) ?

The asymptotes of f(x)=((x^2-9))/(2x+4) is Vertical: x=-2,Slant: y= 1/2 x-1

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asymptotes of f(x)=((x^2-9))/(2x+4)

asymptotes

f (x) = \frac{( x ^{2} - 9 )}{2 x + 4}

Vertical : x = - 2, Slant : y = \frac{1}{2} x - 1

Solution steps

Vertical asymptotes of

\frac{x ^{2} - 9}{2 x + 4} : x = - 2

Horizontal Asymptotes of

\frac{x ^{2} - 9}{2 x + 4} :

None

Slant Asymptotes of

\frac{x ^{2} - 9}{2 x + 4} : y = \frac{1}{2} x - 1

Vertical : x = - 2, Slant : y = \frac{1}{2} x - 1

f (x) = \frac{2 x ^{2} - x + 6}{3 x + 5}

f (x) = \frac{4 x ^{2} - 16}{- 3 x ^{2} + 6 x}

\frac{x + 2}{x ^{2} + 2 x - 3}

f (x) = \frac{1}{x} + x

\frac{x ^{2} - 3 x - 4}{x ^{2} - 16}

What is the asymptotes of f(x)=((x^2-9))/(2x+4) ?
The asymptotes of f(x)=((x^2-9))/(2x+4) is Vertical: x=-2,Slant: y= 1/2 x-1