What is the asymptotes of f(x)=((x^2+1))/((x-1)) ?

The asymptotes of f(x)=((x^2+1))/((x-1)) is Vertical: x=1,Slant: y=x+1

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asymptotes of f(x)=((x^2+1))/((x-1))

asymptotes

f (x) = \frac{( x ^{2} + 1 )}{( x - 1 )}

Vertical : x = 1, Slant : y = x + 1

Solution steps

Vertical asymptotes of

\frac{x ^{2} + 1}{x - 1} : x = 1

Horizontal Asymptotes of

\frac{x ^{2} + 1}{x - 1} :

None

Slant Asymptotes of

\frac{x ^{2} + 1}{x - 1} : y = x + 1

Vertical : x = 1, Slant : y = x + 1

f (x) = 1 + \frac{5}{x} - \frac{9}{x ^{2}}

\frac{x ^{2} - 1}{x ^{2} - 2 x - 3}

f (x) = \frac{( 3 x ^{3} + 30 )}{2 x ^{3}}

f (x) = \frac{6}{x + 4}

f (x) = \frac{( 5 x ^{2} )}{- 3 x ^{2} - 7 x}

What is the asymptotes of f(x)=((x^2+1))/((x-1)) ?
The asymptotes of f(x)=((x^2+1))/((x-1)) is Vertical: x=1,Slant: y=x+1