What is the asymptotes of (-2x^2-4x)/(4x+8) ?

The asymptotes of (-2x^2-4x)/(4x+8) is Slant: y=-1/2 x

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asymptotes of (-2x^2-4x)/(4x+8)

asymptotes

\frac{- 2 x ^{2} - 4 x}{4 x + 8}

Slant : y = - \frac{1}{2} x

Solution steps

Vertical asymptotes of

\frac{- 2 x ^{2} - 4 x}{4 x + 8} :

None

Horizontal Asymptotes of

\frac{- 2 x ^{2} - 4 x}{4 x + 8} :

None

Slant Asymptotes of

\frac{- 2 x ^{2} - 4 x}{4 x + 8} : y = - \frac{1}{2} x

Slant : y = - \frac{1}{2} x

f (x) = \frac{4 x ^{2} + 5 x + 2}{x - 1}

f (x) = x + 6

f (x) = x + 4

f (x) = \frac{- 2 x ^{2}}{x + 2}

f (x) = \frac{3 x ^{2} - 6 x}{( x - 2 ) ^{2}}

What is the asymptotes of (-2x^2-4x)/(4x+8) ?
The asymptotes of (-2x^2-4x)/(4x+8) is Slant: y=-1/2 x