What is the asymptotes of (2x^2+7x+3)/(x^2-9) ?

The asymptotes of (2x^2+7x+3)/(x^2-9) is Vertical: x=3,Horizontal: y=2

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asymptotes of (2x^2+7x+3)/(x^2-9)

asymptotes

\frac{2 x ^{2} + 7 x + 3}{x ^{2} - 9}

Vertical : x = 3, Horizontal : y = 2

Solution steps

Vertical asymptotes of

\frac{2 x ^{2} + 7 x + 3}{x ^{2} - 9} : x = 3

Horizontal Asymptotes of

\frac{2 x ^{2} + 7 x + 3}{x ^{2} - 9} : y = 2

Slant Asymptotes of

\frac{2 x ^{2} + 7 x + 3}{x ^{2} - 9} :

None

Vertical : x = 3, Horizontal : y = 2

2 cos (6 x)

f (x) = - \frac{3}{x - 1}

f (x) = \frac{2}{x - 1} - 3

f (x) = \frac{3 x - 1}{x + 3}

f (x) = \frac{3 x - 1}{x + 1}

What is the asymptotes of (2x^2+7x+3)/(x^2-9) ?
The asymptotes of (2x^2+7x+3)/(x^2-9) is Vertical: x=3,Horizontal: y=2