What is the asymptotes of f(x)=(16x^4-1)/(x^3-x) ?

The asymptotes of f(x)=(16x^4-1)/(x^3-x) is Vertical: x=-1,x=0,x=1,Slant: y=16x

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asymptotes of f(x)=(16x^4-1)/(x^3-x)

asymptotes

f (x) = \frac{16 x ^{4} - 1}{x ^{3} - x}

Vertical : x = - 1, x = 0, x = 1, Slant : y = 16 x

Solution steps

Vertical asymptotes of

\frac{16 x ^{4} - 1}{x ^{3} - x} : x = - 1, x = 0, x = 1

Horizontal Asymptotes of

\frac{16 x ^{4} - 1}{x ^{3} - x} :

None

Slant Asymptotes of

\frac{16 x ^{4} - 1}{x ^{3} - x} : y = 16 x

Vertical : x = - 1, x = 0, x = 1, Slant : y = 16 x

\frac{x - 1}{x - 2}

f (x) = \frac{x - 3}{- 2 x - 8}

\frac{2 x ^{2}}{x - 8}

\frac{2 x ^{2}}{x - 5}

f (x) = \frac{3}{x + 5} - 6

What is the asymptotes of f(x)=(16x^4-1)/(x^3-x) ?
The asymptotes of f(x)=(16x^4-1)/(x^3-x) is Vertical: x=-1,x=0,x=1,Slant: y=16x