What is the asymptotes of f(x)=(x^2-6x+12)/(x-4) ?

The asymptotes of f(x)=(x^2-6x+12)/(x-4) is Vertical: x=4,Slant: y=x-2

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asymptotes of f(x)=(x^2-6x+12)/(x-4)

asymptotes

f (x) = \frac{x ^{2} - 6 x + 12}{x - 4}

Vertical : x = 4, Slant : y = x - 2

Solution steps

Vertical asymptotes of

\frac{x ^{2} - 6 x + 12}{x - 4} : x = 4

Horizontal Asymptotes of

\frac{x ^{2} - 6 x + 12}{x - 4} :

None

Slant Asymptotes of

\frac{x ^{2} - 6 x + 12}{x - 4} : y = x - 2

Vertical : x = 4, Slant : y = x - 2

f (x) = 4 x^{3} - x^{4}

\frac{x ^{2} - x - 2}{x ^{3} - x ^{2} - x + 1}

\frac{10 x ( 54 - 2 x )}{x - x ^{2}}

\frac{x ^{2} - 2 x - 3}{2 x ^{2} - x - 10}

f (x) = 1 - \frac{1}{x}

What is the asymptotes of f(x)=(x^2-6x+12)/(x-4) ?
The asymptotes of f(x)=(x^2-6x+12)/(x-4) is Vertical: x=4,Slant: y=x-2