What is the asymptotes of f(x)=(-4x^2-8x+5)/(2x+1) ?

The asymptotes of f(x)=(-4x^2-8x+5)/(2x+1) is Vertical: x=-1/2 ,Slant: y=-2x-3

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asymptotes of f(x)=(-4x^2-8x+5)/(2x+1)

asymptotes

f (x) = \frac{- 4 x ^{2} - 8 x + 5}{2 x + 1}

Vertical : x = - \frac{1}{2}, Slant : y = - 2 x - 3

Solution steps

Vertical asymptotes of

\frac{- 4 x ^{2} - 8 x + 5}{2 x + 1} : x = - \frac{1}{2}

Horizontal Asymptotes of

\frac{- 4 x ^{2} - 8 x + 5}{2 x + 1} :

None

Slant Asymptotes of

\frac{- 4 x ^{2} - 8 x + 5}{2 x + 1} : y = - 2 x - 3

Vertical : x = - \frac{1}{2}, Slant : y = - 2 x - 3

f (x) = \frac{x ^{2} + 2 x + 1}{8 x ^{2} - x - 9}

y = - 3 sec (2 x)

f (x) = \frac{x ^{3} - 27}{- x ^{3} - 27 x ^{2}}

y = (\frac{2}{3})^{x}

\frac{7}{( x - 8 ) ^{3}}

What is the asymptotes of f(x)=(-4x^2-8x+5)/(2x+1) ?
The asymptotes of f(x)=(-4x^2-8x+5)/(2x+1) is Vertical: x=-1/2 ,Slant: y=-2x-3