What is the asymptotes of f(x)=(2x+1)/(sqrt(x^2-9)) ?

The asymptotes of f(x)=(2x+1)/(sqrt(x^2-9)) is Vertical: x=-3,x=3,Horizontal: y=2,y=-2

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asymptotes of f(x)=(2x+1)/(sqrt(x^2-9))

asymptotes

f (x) = \frac{2 x + 1}{x ^{2} - 9}

Vertical : x = - 3, x = 3, Horizontal : y = 2, y = - 2

Solution steps

Vertical asymptotes of

\frac{2 x + 1}{x ^{2} - 9} : x = - 3, x = 3

Horizontal Asymptotes of

\frac{2 x + 1}{x ^{2} - 9} : y = 2, y = - 2

Slant Asymptotes of

\frac{2 x + 1}{x ^{2} - 9} :

None

Vertical : x = - 3, x = 3, Horizontal : y = 2, y = - 2

f (x) = 0. 8^{x}

\frac{x + 7}{7 x + 49}

10 - 6 ln (x)

f (x) = - 3^{x - 1} - 3

\frac{49 x ^{2}}{7 x - 7}

What is the asymptotes of f(x)=(2x+1)/(sqrt(x^2-9)) ?
The asymptotes of f(x)=(2x+1)/(sqrt(x^2-9)) is Vertical: x=-3,x=3,Horizontal: y=2,y=-2