What is the asymptotes of f(x)=(2x^2-5)/(x+1) ?

The asymptotes of f(x)=(2x^2-5)/(x+1) is Vertical: x=-1,Slant: y=2x-2

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asymptotes of f(x)=(2x^2-5)/(x+1)

asymptotes

f (x) = \frac{2 x ^{2} - 5}{x + 1}

Vertical : x = - 1, Slant : y = 2 x - 2

Solution steps

Vertical asymptotes of

\frac{2 x ^{2} - 5}{x + 1} : x = - 1

Horizontal Asymptotes of

\frac{2 x ^{2} - 5}{x + 1} :

None

Slant Asymptotes of

\frac{2 x ^{2} - 5}{x + 1} : y = 2 x - 2

Vertical : x = - 1, Slant : y = 2 x - 2

f (x) = \frac{x ^{2} + 1}{x - 7}

f (x) = \frac{4 x - 4}{x ^{2} - 4}

f (x) = \frac{x + 12}{x ^{2} - 2 x - 24}

f (x) = \frac{( x - 5 )}{( x + 5 ) ( x - 10 )}

f (x) = \frac{1}{x + 5} + 2

What is the asymptotes of f(x)=(2x^2-5)/(x+1) ?
The asymptotes of f(x)=(2x^2-5)/(x+1) is Vertical: x=-1,Slant: y=2x-2