What is the asymptotes of f(θ)=-2sec(3θ-pi/2)+1 ?

The asymptotes of f(θ)=-2sec(3θ-pi/2)+1 is Vertical: θ=(2pi)/3 n,θ= pi/3+(2pi)/3 n

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asymptotes of f(θ)=-2sec(3θ-pi/2)+1

asymptotes

f (θ) = - 2 sec (3 θ - \frac{π}{2}) + 1

Vertical : θ = \frac{2 π}{3} n, θ = \frac{π}{3} + \frac{2 π}{3} n

Solution steps

Vertical asymptotes of

- 2 sec (3 θ - \frac{π}{2}) + 1 : θ = \frac{2 π}{3} n, θ = \frac{π}{3} + \frac{2 π}{3} n

Horizontal Asymptotes of

- 2 sec (3 θ - \frac{π}{2}) + 1 :

None

Slant Asymptotes of

- 2 sec (3 θ - \frac{π}{2}) + 1 :

None

Vertical : θ = \frac{2 π}{3} n, θ = \frac{π}{3} + \frac{2 π}{3} n

sec (x) tan (x)

\frac{e ^{2 x} + \frac{1}{x} + 2}{3 - e ^{x}}

f (x) = \frac{x ^{2} + 1}{x + 2}

x^{2} + 9

\frac{x ^{2} - x - 6}{x ^{2} - 2 x}

What is the asymptotes of f(θ)=-2sec(3θ-pi/2)+1 ?
The asymptotes of f(θ)=-2sec(3θ-pi/2)+1 is Vertical: θ=(2pi)/3 n,θ= pi/3+(2pi)/3 n