What is the asymptotes of f(x)=(2x^2+7x-13)/(x+5) ?

The asymptotes of f(x)=(2x^2+7x-13)/(x+5) is Vertical: x=-5,Slant: y=2x-3

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asymptotes of f(x)=(2x^2+7x-13)/(x+5)

asymptotes

f (x) = \frac{2 x ^{2} + 7 x - 13}{x + 5}

Vertical : x = - 5, Slant : y = 2 x - 3

Solution steps

Vertical asymptotes of

\frac{2 x ^{2} + 7 x - 13}{x + 5} : x = - 5

Horizontal Asymptotes of

\frac{2 x ^{2} + 7 x - 13}{x + 5} :

None

Slant Asymptotes of

\frac{2 x ^{2} + 7 x - 13}{x + 5} : y = 2 x - 3

Vertical : x = - 5, Slant : y = 2 x - 3

f (h) = \frac{( 3 + h ) ^{- 1} - 3 ^{- 1}}{h}

y = 2 sec (8 x)

\frac{2 x - 7}{5 x + 3}

f (x) = \frac{( 4 x + 1 )}{( 2 x - 5 )}

f (x) = \frac{x ^{2} + x}{x ( x - 6 )}

What is the asymptotes of f(x)=(2x^2+7x-13)/(x+5) ?
The asymptotes of f(x)=(2x^2+7x-13)/(x+5) is Vertical: x=-5,Slant: y=2x-3