What is the asymptotes of y=(4x)/(x^2-9) ?

The asymptotes of y=(4x)/(x^2-9) is Vertical: x=-3,x=3,Horizontal: y=0

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asymptotes of y=(4x)/(x^2-9)

asymptotes

y = \frac{4 x}{x ^{2} - 9}

Vertical : x = - 3, x = 3, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{4 x}{x ^{2} - 9} : x = - 3, x = 3

Horizontal Asymptotes of

\frac{4 x}{x ^{2} - 9} : y = 0

Slant Asymptotes of

\frac{4 x}{x ^{2} - 9} :

None

Vertical : x = - 3, x = 3, Horizontal : y = 0

y = \frac{2 x ^{2} - 4 x}{x ^{2} - 1}

f (x) = \frac{1}{1 - x}

5^{x} - 2

f (x) = \frac{3 x ^{2} + 1}{x ^{2} + 6 x - 7}

f (x) = \frac{- 3 x ^{2}}{x ^{2} + 6 x - 40}

What is the asymptotes of y=(4x)/(x^2-9) ?
The asymptotes of y=(4x)/(x^2-9) is Vertical: x=-3,x=3,Horizontal: y=0