What is the asymptotes of f(x)=(2x^2-8x+8)/(-x^2+4x) ?

The asymptotes of f(x)=(2x^2-8x+8)/(-x^2+4x) is Vertical: x=0,x=4,Horizontal: y=-2

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asymptotes of f(x)=(2x^2-8x+8)/(-x^2+4x)

asymptotes

f (x) = \frac{2 x ^{2} - 8 x + 8}{- x ^{2} + 4 x}

Vertical : x = 0, x = 4, Horizontal : y = - 2

Solution steps

Vertical asymptotes of

\frac{2 x ^{2} - 8 x + 8}{- x ^{2} + 4 x} : x = 0, x = 4

Horizontal Asymptotes of

\frac{2 x ^{2} - 8 x + 8}{- x ^{2} + 4 x} : y = - 2

Slant Asymptotes of

\frac{2 x ^{2} - 8 x + 8}{- x ^{2} + 4 x} :

None

Vertical : x = 0, x = 4, Horizontal : y = - 2

f (x) = lo g_{3} (x^{2} - 8)

\frac{x}{x ^{2} + 7}

y = 4 \cdot (\frac{1}{2})^{x - 2} + 1

f (x) = \frac{3 x ^{2} - 5}{2 - x}

\frac{6}{x + 7}

What is the asymptotes of f(x)=(2x^2-8x+8)/(-x^2+4x) ?
The asymptotes of f(x)=(2x^2-8x+8)/(-x^2+4x) is Vertical: x=0,x=4,Horizontal: y=-2