What is the asymptotes of f(x)=(x^2+2x-12)/(x-5) ?

The asymptotes of f(x)=(x^2+2x-12)/(x-5) is Vertical: x=5,Slant: y=x+7

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asymptotes of f(x)=(x^2+2x-12)/(x-5)

asymptotes

f (x) = \frac{x ^{2} + 2 x - 12}{x - 5}

Vertical : x = 5, Slant : y = x + 7

Solution steps

Vertical asymptotes of

\frac{x ^{2} + 2 x - 12}{x - 5} : x = 5

Horizontal Asymptotes of

\frac{x ^{2} + 2 x - 12}{x - 5} :

None

Slant Asymptotes of

\frac{x ^{2} + 2 x - 12}{x - 5} : y = x + 7

Vertical : x = 5, Slant : y = x + 7

\frac{x ^{2} + x - 6}{x ^{2} - x - 2}

f (x) = \frac{x ^{3} - x}{x ^{2} - 4}

f (x) = \frac{x ^{2} - x - 2}{x ^{2} - 2 x - 3}

g (x) = 2^{x - 2}

x^{2} + x - 1

What is the asymptotes of f(x)=(x^2+2x-12)/(x-5) ?
The asymptotes of f(x)=(x^2+2x-12)/(x-5) is Vertical: x=5,Slant: y=x+7