What is the asymptotes of f(x)=((2x^2+x))/(x-1) ?

The asymptotes of f(x)=((2x^2+x))/(x-1) is Vertical: x=1,Slant: y=2x+3

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asymptotes of f(x)=((2x^2+x))/(x-1)

asymptotes

f (x) = \frac{( 2 x ^{2} + x )}{x - 1}

Vertical : x = 1, Slant : y = 2 x + 3

Solution steps

Vertical asymptotes of

\frac{2 x ^{2} + x}{x - 1} : x = 1

Horizontal Asymptotes of

\frac{2 x ^{2} + x}{x - 1} :

None

Slant Asymptotes of

\frac{2 x ^{2} + x}{x - 1} : y = 2 x + 3

Vertical : x = 1, Slant : y = 2 x + 3

f (x) = ln (8 - ln (x))

f (x) = 5^{x} - 6

sin (\frac{1 - 9 x}{x})

f (x) = \frac{4}{x ^{2} - x - 6}

f (x) = 5^{x} + 1

What is the asymptotes of f(x)=((2x^2+x))/(x-1) ?
The asymptotes of f(x)=((2x^2+x))/(x-1) is Vertical: x=1,Slant: y=2x+3