What is the asymptotes of f(x)=(x+4)/(x^2+x-12) ?

The asymptotes of f(x)=(x+4)/(x^2+x-12) is Vertical: x=3,Horizontal: y=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

asymptotes of f(x)=(x+4)/(x^2+x-12)

asymptotes

f (x) = \frac{x + 4}{x ^{2} + x - 12}

Vertical : x = 3, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{x + 4}{x ^{2} + x - 12} : x = 3

Horizontal Asymptotes of

\frac{x + 4}{x ^{2} + x - 12} : y = 0

Slant Asymptotes of

\frac{x + 4}{x ^{2} + x - 12} :

None

Vertical : x = 3, Horizontal : y = 0

\frac{x - 2}{x ^{4} - 16}

f (x) = \frac{2 x ^{2} - 14 x}{2 x - 14}

\frac{5 x - 11}{2 x + 3}

\frac{x + 2}{x ^{2} - 3 x - 10}

f (x) = \frac{( x - 5 )}{2 x ^{2} - 50}

What is the asymptotes of f(x)=(x+4)/(x^2+x-12) ?
The asymptotes of f(x)=(x+4)/(x^2+x-12) is Vertical: x=3,Horizontal: y=0