What is the asymptotes of f(x)=(4x^2-4x+5)/(2x-1) ?

The asymptotes of f(x)=(4x^2-4x+5)/(2x-1) is Vertical: x= 1/2 ,Slant: y=2x-1

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asymptotes of f(x)=(4x^2-4x+5)/(2x-1)

asymptotes

f (x) = \frac{4 x ^{2} - 4 x + 5}{2 x - 1}

Vertical : x = \frac{1}{2}, Slant : y = 2 x - 1

Solution steps

Vertical asymptotes of

\frac{4 x ^{2} - 4 x + 5}{2 x - 1} : x = \frac{1}{2}

Horizontal Asymptotes of

\frac{4 x ^{2} - 4 x + 5}{2 x - 1} :

None

Slant Asymptotes of

\frac{4 x ^{2} - 4 x + 5}{2 x - 1} : y = 2 x - 1

Vertical : x = \frac{1}{2}, Slant : y = 2 x - 1

ln (5 - ln (x))

f (x) = \frac{2 ^{2 x} - 5}{4 ^{x} + 10}

f (x) = \frac{10 x}{5 x ^{2} + 1}

f (x) = \frac{1}{2 x - 6}

f (x) = \frac{x ^{2} + 4 x}{x ^{2} - 16}

What is the asymptotes of f(x)=(4x^2-4x+5)/(2x-1) ?
The asymptotes of f(x)=(4x^2-4x+5)/(2x-1) is Vertical: x= 1/2 ,Slant: y=2x-1