What is the asymptotes of f(x)=(2x^2+7x+3)/(x^2-9) ?

The asymptotes of f(x)=(2x^2+7x+3)/(x^2-9) is Vertical: x=3,Horizontal: y=2

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asymptotes of f(x)=(2x^2+7x+3)/(x^2-9)

asymptotes

f (x) = \frac{2 x ^{2} + 7 x + 3}{x ^{2} - 9}

Vertical : x = 3, Horizontal : y = 2

Solution steps

Vertical asymptotes of

\frac{2 x ^{2} + 7 x + 3}{x ^{2} - 9} : x = 3

Horizontal Asymptotes of

\frac{2 x ^{2} + 7 x + 3}{x ^{2} - 9} : y = 2

Slant Asymptotes of

\frac{2 x ^{2} + 7 x + 3}{x ^{2} - 9} :

None

Vertical : x = 3, Horizontal : y = 2

f (x) = \frac{2 x + 6}{x - 1}

f (x) = \frac{x ^{2} - 16}{2 x ^{2} - 5 x + 3}

y = \frac{x ^{4}}{x ^{4} - 256}

f (x) = arctan (e^{5 x} - 1)

f (x) = - (0.75)^{x} + 3

What is the asymptotes of f(x)=(2x^2+7x+3)/(x^2-9) ?
The asymptotes of f(x)=(2x^2+7x+3)/(x^2-9) is Vertical: x=3,Horizontal: y=2