What is the asymptotes of f(x)=(x^3+x^2+3)/(x^2-9) ?

The asymptotes of f(x)=(x^3+x^2+3)/(x^2-9) is Vertical: x=-3,x=3,Slant: y=x+1

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asymptotes of f(x)=(x^3+x^2+3)/(x^2-9)

asymptotes

f (x) = \frac{x ^{3} + x ^{2} + 3}{x ^{2} - 9}

Vertical : x = - 3, x = 3, Slant : y = x + 1

Solution steps

Vertical asymptotes of

\frac{x ^{3} + x ^{2} + 3}{x ^{2} - 9} : x = - 3, x = 3

Horizontal Asymptotes of

\frac{x ^{3} + x ^{2} + 3}{x ^{2} - 9} :

None

Slant Asymptotes of

\frac{x ^{3} + x ^{2} + 3}{x ^{2} - 9} : y = x + 1

Vertical : x = - 3, x = 3, Slant : y = x + 1

f (x) = \frac{( x + 7 )}{( x + 3 ) ( x - 5 )}

f (x) = - 2^{(- 2 + 3 x)} - 4

f (x) = \frac{1}{25 - x ^{2}}

f (x) = \frac{6 x + 2}{3 x - 12}

\frac{- 3 x}{x - 2}

What is the asymptotes of f(x)=(x^3+x^2+3)/(x^2-9) ?
The asymptotes of f(x)=(x^3+x^2+3)/(x^2-9) is Vertical: x=-3,x=3,Slant: y=x+1