What is the asymptotes of f(x)=(-1)/(x^2(x+1)) ?

The asymptotes of f(x)=(-1)/(x^2(x+1)) is Vertical: x=-1,x=0,Horizontal: y=0

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asymptotes of f(x)=(-1)/(x^2(x+1))

asymptotes

f (x) = \frac{- 1}{x ^{2} ( x + 1 )}

Vertical : x = - 1, x = 0, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{- 1}{x ^{2} ( x + 1 )} : x = - 1, x = 0

Horizontal Asymptotes of

\frac{- 1}{x ^{2} ( x + 1 )} : y = 0

Slant Asymptotes of

\frac{- 1}{x ^{2} ( x + 1 )} :

None

Vertical : x = - 1, x = 0, Horizontal : y = 0

f (x) = \frac{x ^{3} - 2 x ^{2} + 5}{x ^{2}}

y = \frac{2 x - 1}{x ^{2} - 5 x + 6}

f (x) = \frac{4}{x ^{2} + 9}

\frac{4 x - 60}{( x - 103 ) ^{9}}

f (x) = - \frac{1}{e ^{\frac{1}{x}}}

What is the asymptotes of f(x)=(-1)/(x^2(x+1)) ?
The asymptotes of f(x)=(-1)/(x^2(x+1)) is Vertical: x=-1,x=0,Horizontal: y=0