What is the asymptotes of f(x)=arctan(-e^{4x}+1) ?

The asymptotes of f(x)=arctan(-e^{4x}+1) is Horizontal: y=-pi/2 ,y= pi/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

asymptotes of f(x)=arctan(-e^{4x}+1)

asymptotes

f (x) = arctan (- e^{4 x} + 1)

Horizontal : y = - \frac{π}{2}, y = \frac{π}{4}

Solution steps

Vertical asymptotes of

arctan (- e^{4 x} + 1) :

None

Horizontal Asymptotes of

arctan (- e^{4 x} + 1) : y = - \frac{π}{2}, y = \frac{π}{4}

Slant Asymptotes of

arctan (- e^{4 x} + 1) :

None

Horizontal : y = - \frac{π}{2}, y = \frac{π}{4}

f (x) = \frac{( x + 1 ) ^{2}}{e ^{x}}

f (x) = \frac{2 x - 4}{x - 1}

\frac{4 x - 5}{x + 1}

f (x) = \frac{3 x ^{2} + x - 2}{2 x - 1}

\frac{x ^{2} + 2 x + 3}{x - 4}

What is the asymptotes of f(x)=arctan(-e^{4x}+1) ?
The asymptotes of f(x)=arctan(-e^{4x}+1) is Horizontal: y=-pi/2 ,y= pi/4