What is the asymptotes of f(x)= 1/(x^2+x-12) ?

The asymptotes of f(x)= 1/(x^2+x-12) is Vertical: x=-4,x=3,Horizontal: y=0

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asymptotes of f(x)= 1/(x^2+x-12)

asymptotes

f (x) = \frac{1}{x ^{2} + x - 12}

Vertical : x = - 4, x = 3, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{1}{x ^{2} + x - 12} : x = - 4, x = 3

Horizontal Asymptotes of

\frac{1}{x ^{2} + x - 12} : y = 0

Slant Asymptotes of

\frac{1}{x ^{2} + x - 12} :

None

Vertical : x = - 4, x = 3, Horizontal : y = 0

f (x) = \frac{3 x - 7}{x ^{2} - 1}

f (x) = \frac{x - 2}{e ^{x}}

- 4 tan (4 θ + \frac{π}{5})

\frac{x ^{3} - 64}{x ^{2} - 3 x - 4}

f (x) = \frac{x}{- 2 x + 3}

What is the asymptotes of f(x)= 1/(x^2+x-12) ?
The asymptotes of f(x)= 1/(x^2+x-12) is Vertical: x=-4,x=3,Horizontal: y=0