What is the asymptotes of f(x)=((x-8)(x+1))/(x^2-9) ?

The asymptotes of f(x)=((x-8)(x+1))/(x^2-9) is Vertical: x=-3,x=3,Horizontal: y=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

asymptotes of f(x)=((x-8)(x+1))/(x^2-9)

asymptotes

f (x) = \frac{( x - 8 ) ( x + 1 )}{x ^{2} - 9}

Vertical : x = - 3, x = 3, Horizontal : y = 1

Solution steps

Vertical asymptotes of

\frac{( x - 8 ) ( x + 1 )}{x ^{2} - 9} : x = - 3, x = 3

Horizontal Asymptotes of

\frac{( x - 8 ) ( x + 1 )}{x ^{2} - 9} : y = 1

Slant Asymptotes of

\frac{( x - 8 ) ( x + 1 )}{x ^{2} - 9} :

None

Vertical : x = - 3, x = 3, Horizontal : y = 1

f (x) = \frac{5 x ^{4} - 2 x}{x ^{4} + 32}

f (x) = \frac{x + 7}{x ^{2} - 4}

\frac{25 x ^{2}}{5 x ^{2} + 1}

y = - 3 (x - 2)^{2} + 2

\frac{7 x}{x ^{2} - 36}

What is the asymptotes of f(x)=((x-8)(x+1))/(x^2-9) ?
The asymptotes of f(x)=((x-8)(x+1))/(x^2-9) is Vertical: x=-3,x=3,Horizontal: y=1