What is the asymptotes of f(x)=((2x^2))/(2x-8) ?

The asymptotes of f(x)=((2x^2))/(2x-8) is Vertical: x=4,Slant: y=x+4

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asymptotes of f(x)=((2x^2))/(2x-8)

asymptotes

f (x) = \frac{( 2 x ^{2} )}{2 x - 8}

Vertical : x = 4, Slant : y = x + 4

Solution steps

Vertical asymptotes of

\frac{2 x ^{2}}{2 x - 8} : x = 4

Horizontal Asymptotes of

\frac{2 x ^{2}}{2 x - 8} :

None

Slant Asymptotes of

\frac{2 x ^{2}}{2 x - 8} : y = x + 4

Vertical : x = 4, Slant : y = x + 4

f (x) = \frac{( 3 x + 1 )}{( x - 2 )}

\frac{2 e ^{x} + x ^{2}}{x - 1}

f (x) = \frac{14 x ^{2}}{x - 8}

\frac{x ^{3} + 2 x}{x ^{2} - 2 x - 3}

f (x) = \frac{x ^{2} + 5 x + 6}{x ^{2} + 4 x + 1}

What is the asymptotes of f(x)=((2x^2))/(2x-8) ?
The asymptotes of f(x)=((2x^2))/(2x-8) is Vertical: x=4,Slant: y=x+4