What is the asymptotes of f(x)=(-6x^2-5x+1)/(2x+1) ?

The asymptotes of f(x)=(-6x^2-5x+1)/(2x+1) is Vertical: x=-1/2 ,Slant: y=-3x-1

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asymptotes of f(x)=(-6x^2-5x+1)/(2x+1)

asymptotes

f (x) = \frac{- 6 x ^{2} - 5 x + 1}{2 x + 1}

Vertical : x = - \frac{1}{2}, Slant : y = - 3 x - 1

Solution steps

Vertical asymptotes of

\frac{- 6 x ^{2} - 5 x + 1}{2 x + 1} : x = - \frac{1}{2}

Horizontal Asymptotes of

\frac{- 6 x ^{2} - 5 x + 1}{2 x + 1} :

None

Slant Asymptotes of

\frac{- 6 x ^{2} - 5 x + 1}{2 x + 1} : y = - 3 x - 1

Vertical : x = - \frac{1}{2}, Slant : y = - 3 x - 1

f (x) = 3 + \frac{( 3 x + 2 )}{x}

f (x) = \frac{( 3 x - 2 )}{( x + 1 )}

f (x) = 3^{x - 1} + 2

f (x) = \frac{x ^{2} + 5 x + 6}{x ^{2} + 4 x - 5}

f (x) = \frac{5}{x} - 2

What is the asymptotes of f(x)=(-6x^2-5x+1)/(2x+1) ?
The asymptotes of f(x)=(-6x^2-5x+1)/(2x+1) is Vertical: x=-1/2 ,Slant: y=-3x-1