What is the asymptotes of y=(x^2-4)/(x^2-9) ?

The asymptotes of y=(x^2-4)/(x^2-9) is Vertical: x=-3,x=3,Horizontal: y=1

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asymptotes of y=(x^2-4)/(x^2-9)

asymptotes

y = \frac{x ^{2} - 4}{x ^{2} - 9}

Vertical : x = - 3, x = 3, Horizontal : y = 1

Solution steps

Vertical asymptotes of

\frac{x ^{2} - 4}{x ^{2} - 9} : x = - 3, x = 3

Horizontal Asymptotes of

\frac{x ^{2} - 4}{x ^{2} - 9} : y = 1

Slant Asymptotes of

\frac{x ^{2} - 4}{x ^{2} - 9} :

None

Vertical : x = - 3, x = 3, Horizontal : y = 1

f (x) = x^{2} + 2 x

\frac{4 x ^{2}}{x ^{2} - 25}

f (x) = \frac{x}{x ^{2} - 2 x + 1}

\frac{7}{x ^{2} - 25}

\frac{4 x - 8}{x ^{2} - 4 x + 4}

What is the asymptotes of y=(x^2-4)/(x^2-9) ?
The asymptotes of y=(x^2-4)/(x^2-9) is Vertical: x=-3,x=3,Horizontal: y=1