What is the asymptotes of f(x)=((x^2-2x))/(x^4-16) ?

The asymptotes of f(x)=((x^2-2x))/(x^4-16) is Vertical: x=-2,Horizontal: y=0

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asymptotes of f(x)=((x^2-2x))/(x^4-16)

asymptotes

f (x) = \frac{( x ^{2} - 2 x )}{x ^{4} - 16}

Vertical : x = - 2, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{x ^{2} - 2 x}{x ^{4} - 16} : x = - 2

Horizontal Asymptotes of

\frac{x ^{2} - 2 x}{x ^{4} - 16} : y = 0

Slant Asymptotes of

\frac{x ^{2} - 2 x}{x ^{4} - 16} :

None

Vertical : x = - 2, Horizontal : y = 0

f (x) = 5^{x + 3}

\frac{1}{x ^{2} - x}

f (x) = \frac{x ^{2} - 9}{x ^{3} + 27}

f (x) = \frac{ln ( 2 x + 8 )}{x + 4} + 2

f (x) = \frac{( x + 2 )}{x ^{2} - 16}

What is the asymptotes of f(x)=((x^2-2x))/(x^4-16) ?
The asymptotes of f(x)=((x^2-2x))/(x^4-16) is Vertical: x=-2,Horizontal: y=0