What is the asymptotes of f(x)=((x^2+1))/((x^2-4)) ?

The asymptotes of f(x)=((x^2+1))/((x^2-4)) is Vertical: x=-2,x=2,Horizontal: y=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

asymptotes of f(x)=((x^2+1))/((x^2-4))

asymptotes

f (x) = \frac{( x ^{2} + 1 )}{( x ^{2} - 4 )}

Vertical : x = - 2, x = 2, Horizontal : y = 1

Solution steps

Vertical asymptotes of

\frac{x ^{2} + 1}{x ^{2} - 4} : x = - 2, x = 2

Horizontal Asymptotes of

\frac{x ^{2} + 1}{x ^{2} - 4} : y = 1

Slant Asymptotes of

\frac{x ^{2} + 1}{x ^{2} - 4} :

None

Vertical : x = - 2, x = 2, Horizontal : y = 1

f (x) = (x^{2} + 11) \cdot (4 - x^{2})

\frac{( 2 x ^{2} - 3 x - 1 )}{2 x + 1}

f (x) = ln (x - 10)

3 lo g_{10} (x - 1)

- sec (x - \frac{π}{3}) - 2

What is the asymptotes of f(x)=((x^2+1))/((x^2-4)) ?
The asymptotes of f(x)=((x^2+1))/((x^2-4)) is Vertical: x=-2,x=2,Horizontal: y=1