What is the asymptotes of f(x)=(8-e^x)/(2+e^x) ?

The asymptotes of f(x)=(8-e^x)/(2+e^x) is Horizontal: y=-1,y=4

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asymptotes of f(x)=(8-e^x)/(2+e^x)

asymptotes

f (x) = \frac{8 - e ^{x}}{2 + e ^{x}}

Horizontal : y = - 1, y = 4

Solution steps

Vertical asymptotes of

\frac{8 - e ^{x}}{2 + e ^{x}} :

None

Horizontal Asymptotes of

\frac{8 - e ^{x}}{2 + e ^{x}} : y = - 1, y = 4

Slant Asymptotes of

\frac{8 - e ^{x}}{2 + e ^{x}} :

None

Horizontal : y = - 1, y = 4

f (x) = x \cdot arctan (x)

f (x) = \frac{4 x ^{2} + 2}{x ^{2} - 3 x}

h (x) = \frac{10 x ^{3}}{5 x ^{2} + 1}

y = \frac{x ^{2}}{x - 5}

f (x) = \frac{x ^{2} - 12 x + 25}{x - 2}

What is the asymptotes of f(x)=(8-e^x)/(2+e^x) ?
The asymptotes of f(x)=(8-e^x)/(2+e^x) is Horizontal: y=-1,y=4