What is the asymptotes of f(x)=(x^2)/(2x-8) ?

The asymptotes of f(x)=(x^2)/(2x-8) is Vertical: x=4,Slant: y= 1/2 x+2

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asymptotes of f(x)=(x^2)/(2x-8)

asymptotes

f (x) = \frac{x ^{2}}{2 x - 8}

Vertical : x = 4, Slant : y = \frac{1}{2} x + 2

Solution steps

Vertical asymptotes of

\frac{x ^{2}}{2 x - 8} : x = 4

Horizontal Asymptotes of

\frac{x ^{2}}{2 x - 8} :

None

Slant Asymptotes of

\frac{x ^{2}}{2 x - 8} : y = \frac{1}{2} x + 2

Vertical : x = 4, Slant : y = \frac{1}{2} x + 2

f (x) = \frac{x - 1}{x ^{2} - x}

f (x) = 5 x + 1

f (x) = 5 x + 3

f (x) = \frac{x + 5}{( x + 2 ) ( x - 3 )}

f (x) = \frac{3 x - 2}{x + 4}

What is the asymptotes of f(x)=(x^2)/(2x-8) ?
The asymptotes of f(x)=(x^2)/(2x-8) is Vertical: x=4,Slant: y= 1/2 x+2