What is the asymptotes of (x^2+5x-5)/(x+1) ?

The asymptotes of (x^2+5x-5)/(x+1) is Vertical: x=-1,Slant: y=x+4

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asymptotes of (x^2+5x-5)/(x+1)

asymptotes

\frac{x ^{2} + 5 x - 5}{x + 1}

Vertical : x = - 1, Slant : y = x + 4

Solution steps

Vertical asymptotes of

\frac{x ^{2} + 5 x - 5}{x + 1} : x = - 1

Horizontal Asymptotes of

\frac{x ^{2} + 5 x - 5}{x + 1} :

None

Slant Asymptotes of

\frac{x ^{2} + 5 x - 5}{x + 1} : y = x + 4

Vertical : x = - 1, Slant : y = x + 4

\frac{x - 7}{x + 5}

f (x) = lo g_{2} (x - 5) - 4

f (x) = \frac{5}{x ^{2} - 36}

f (x) = \frac{4}{( x - 3 ) ^{2}}

\frac{2 x ^{5} - 8 x + 8}{9 x ^{2} + 5 x + 8}

What is the asymptotes of (x^2+5x-5)/(x+1) ?
The asymptotes of (x^2+5x-5)/(x+1) is Vertical: x=-1,Slant: y=x+4