What is the asymptotes of y=(2x^2+x-18)/(x^2-9) ?

The asymptotes of y=(2x^2+x-18)/(x^2-9) is Vertical: x=-3,x=3,Horizontal: y=2

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asymptotes of y=(2x^2+x-18)/(x^2-9)

asymptotes

y = \frac{2 x ^{2} + x - 18}{x ^{2} - 9}

Vertical : x = - 3, x = 3, Horizontal : y = 2

Solution steps

Vertical asymptotes of

\frac{2 x ^{2} + x - 18}{x ^{2} - 9} : x = - 3, x = 3

Horizontal Asymptotes of

\frac{2 x ^{2} + x - 18}{x ^{2} - 9} : y = 2

Slant Asymptotes of

\frac{2 x ^{2} + x - 18}{x ^{2} - 9} :

None

Vertical : x = - 3, x = 3, Horizontal : y = 2

y + 1 = - \frac{4}{5} = (x - 4)

y = - x

\frac{4 - x ^{2}}{x}

f (x) = \frac{x ^{2} + 2 x + 1}{x ^{2} + 4 x + 3}

y = \frac{1}{( 2 x - 3 )}

What is the asymptotes of y=(2x^2+x-18)/(x^2-9) ?
The asymptotes of y=(2x^2+x-18)/(x^2-9) is Vertical: x=-3,x=3,Horizontal: y=2