What is the asymptotes of f(x)=(2x^2+3)/(x+1) ?

The asymptotes of f(x)=(2x^2+3)/(x+1) is Vertical: x=-1,Slant: y=2x-2

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asymptotes of f(x)=(2x^2+3)/(x+1)

asymptotes

f (x) = \frac{2 x ^{2} + 3}{x + 1}

Vertical : x = - 1, Slant : y = 2 x - 2

Solution steps

Vertical asymptotes of

\frac{2 x ^{2} + 3}{x + 1} : x = - 1

Horizontal Asymptotes of

\frac{2 x ^{2} + 3}{x + 1} :

None

Slant Asymptotes of

\frac{2 x ^{2} + 3}{x + 1} : y = 2 x - 2

Vertical : x = - 1, Slant : y = 2 x - 2

y + 1 = \frac{5}{4} (x - 4)

\frac{2 x ^{2} - 12 x + 18}{4 x ^{2} - 36}

f (x) = arctan (e^{7 x})

{\frac{x}{x - 1} : x < 0, \frac{x}{e ^{x}} : x > 0}

f (x) = \frac{x ^{3} + 4}{x ^{2}}

What is the asymptotes of f(x)=(2x^2+3)/(x+1) ?
The asymptotes of f(x)=(2x^2+3)/(x+1) is Vertical: x=-1,Slant: y=2x-2