What is the asymptotes of f(x)=(2x^2-8x+8)/(x^2-4x) ?

The asymptotes of f(x)=(2x^2-8x+8)/(x^2-4x) is Vertical: x=0,x=4,Horizontal: y=2

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asymptotes of f(x)=(2x^2-8x+8)/(x^2-4x)

asymptotes

f (x) = \frac{2 x ^{2} - 8 x + 8}{x ^{2} - 4 x}

Vertical : x = 0, x = 4, Horizontal : y = 2

Solution steps

Vertical asymptotes of

\frac{2 x ^{2} - 8 x + 8}{x ^{2} - 4 x} : x = 0, x = 4

Horizontal Asymptotes of

\frac{2 x ^{2} - 8 x + 8}{x ^{2} - 4 x} : y = 2

Slant Asymptotes of

\frac{2 x ^{2} - 8 x + 8}{x ^{2} - 4 x} :

None

Vertical : x = 0, x = 4, Horizontal : y = 2

f (x) = \frac{6}{x + 3}

f (x) = \frac{x ^{2} + 7}{x}

f (x) = \frac{( x - 2 x ^{2} - 11 )}{x ^{2} - 3}

y = \frac{x ^{2} + x + 1}{x + 1}

f (x) = \frac{1}{4 - 9 x}

What is the asymptotes of f(x)=(2x^2-8x+8)/(x^2-4x) ?
The asymptotes of f(x)=(2x^2-8x+8)/(x^2-4x) is Vertical: x=0,x=4,Horizontal: y=2