What is the asymptotes of f(x)=(2x)/(sqrt(x^2-1)) ?

The asymptotes of f(x)=(2x)/(sqrt(x^2-1)) is Vertical: x=-1,x=1,Horizontal: y=2,y=-2

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asymptotes of f(x)=(2x)/(sqrt(x^2-1))

asymptotes

f (x) = \frac{2 x}{x ^{2} - 1}

Vertical : x = - 1, x = 1, Horizontal : y = 2, y = - 2

Solution steps

Vertical asymptotes of

\frac{2 x}{x ^{2} - 1} : x = - 1, x = 1

Horizontal Asymptotes of

\frac{2 x}{x ^{2} - 1} : y = 2, y = - 2

Slant Asymptotes of

\frac{2 x}{x ^{2} - 1} :

None

Vertical : x = - 1, x = 1, Horizontal : y = 2, y = - 2

f (x) = 3 x + 6

f (x) = 3 x + 5

f (x) = x^{4} - 4 x

y = \frac{x ^{2} + 1}{2 x ^{2} - 3 x - 2}

\frac{x ^{2} + x - 2}{2 x ^{3} + x ^{2} - 3 x}

What is the asymptotes of f(x)=(2x)/(sqrt(x^2-1)) ?
The asymptotes of f(x)=(2x)/(sqrt(x^2-1)) is Vertical: x=-1,x=1,Horizontal: y=2,y=-2