What is the asymptotes of f(x)=((x^2-3x-4))/(x^2-1) ?

The asymptotes of f(x)=((x^2-3x-4))/(x^2-1) is Vertical: x=1,Horizontal: y=1

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asymptotes of f(x)=((x^2-3x-4))/(x^2-1)

asymptotes

f (x) = \frac{( x ^{2} - 3 x - 4 )}{x ^{2} - 1}

Vertical : x = 1, Horizontal : y = 1

Solution steps

Vertical asymptotes of

\frac{x ^{2} - 3 x - 4}{x ^{2} - 1} : x = 1

Horizontal Asymptotes of

\frac{x ^{2} - 3 x - 4}{x ^{2} - 1} : y = 1

Slant Asymptotes of

\frac{x ^{2} - 3 x - 4}{x ^{2} - 1} :

None

Vertical : x = 1, Horizontal : y = 1

f (x) = \frac{x ^{2} + x - 12}{x ^{2} - x - 6}

f (x) = \frac{3 x + 1}{15 x ^{2} + 11 x + 2}

\frac{( x ^{2} - 4 )}{( 30 x - 15 )}

f (x) = lo g_{a} (x + 3) - 7

f (x) = x^{3} - 3 x^{2}

What is the asymptotes of f(x)=((x^2-3x-4))/(x^2-1) ?
The asymptotes of f(x)=((x^2-3x-4))/(x^2-1) is Vertical: x=1,Horizontal: y=1