What is the asymptotes of f(x)=(sqrt(4x^2+1))/(x+1) ?

The asymptotes of f(x)=(sqrt(4x^2+1))/(x+1) is Vertical: x=-1,Horizontal: y=2,y=-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

asymptotes of f(x)=(sqrt(4x^2+1))/(x+1)

asymptotes

f (x) = \frac{4 x ^{2} + 1}{x + 1}

Vertical : x = - 1, Horizontal : y = 2, y = - 2

Solution steps

Vertical asymptotes of

\frac{4 x ^{2} + 1}{x + 1} : x = - 1

Horizontal Asymptotes of

\frac{4 x ^{2} + 1}{x + 1} : y = 2, y = - 2

Slant Asymptotes of

\frac{4 x ^{2} + 1}{x + 1} :

None

Vertical : x = - 1, Horizontal : y = 2, y = - 2

f (x) = \frac{( - 2 x - 6 )}{x + 3}

\frac{5 x + 6}{x ^{2} - 9}

f (x) = 5^{- x}

f (x) = \frac{x}{x ^{2} + 3}

f (x) = - 2 (4 - \frac{1}{2})^{x} - 3

What is the asymptotes of f(x)=(sqrt(4x^2+1))/(x+1) ?
The asymptotes of f(x)=(sqrt(4x^2+1))/(x+1) is Vertical: x=-1,Horizontal: y=2,y=-2