What is the asymptotes of f(x)=((x-4))/((x^2-9)) ?

The asymptotes of f(x)=((x-4))/((x^2-9)) is Vertical: x=-3,x=3,Horizontal: y=0

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asymptotes of f(x)=((x-4))/((x^2-9))

asymptotes

f (x) = \frac{( x - 4 )}{( x ^{2} - 9 )}

Vertical : x = - 3, x = 3, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{x - 4}{x ^{2} - 9} : x = - 3, x = 3

Horizontal Asymptotes of

\frac{x - 4}{x ^{2} - 9} : y = 0

Slant Asymptotes of

\frac{x - 4}{x ^{2} - 9} :

None

Vertical : x = - 3, x = 3, Horizontal : y = 0

f (x) = x 36 - x^{2}

f (x) = \frac{5 x + 20}{x ^{2} - 3 x - 10}

x + \frac{2}{x}

f (x) = \frac{x ( x - 1 )}{( x + 2 ) ( x - 4 )}

3 lo g_{4} (x + 2)

What is the asymptotes of f(x)=((x-4))/((x^2-9)) ?
The asymptotes of f(x)=((x-4))/((x^2-9)) is Vertical: x=-3,x=3,Horizontal: y=0