What is the asymptotes of y=sec(2x) ?

The asymptotes of y=sec(2x) is Vertical: x=(3pi)/4+pin,x= pi/4+pin

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asymptotes of y=sec(2x)

asymptotes

y = sec (2 x)

Vertical : x = \frac{3 π}{4} + πn, x = \frac{π}{4} + πn

Solution steps

Vertical asymptotes of

sec (2 x) : x = \frac{3 π}{4} + πn, x = \frac{π}{4} + πn

Horizontal Asymptotes of

sec (2 x) :

None

Slant Asymptotes of

sec (2 x) :

None

Vertical : x = \frac{3 π}{4} + πn, x = \frac{π}{4} + πn

f (x) = \frac{( 3 x - 3 x ^{2} )}{x + 1}

y = lo g_{2} (x - 1) + 2

g (x) = e^{x - 2} - 1

f (x) = \frac{x + 2}{2 x + 1}

f (x) = \frac{x ^{2} + 4 x - 5}{x ^{2} + x - 2}

What is the asymptotes of y=sec(2x) ?
The asymptotes of y=sec(2x) is Vertical: x=(3pi)/4+pin,x= pi/4+pin