What is the asymptotes of f(x)=(x^2-2x-8)/(x^2-x-12) ?

The asymptotes of f(x)=(x^2-2x-8)/(x^2-x-12) is Vertical: x=-3,Horizontal: y=1

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asymptotes of f(x)=(x^2-2x-8)/(x^2-x-12)

asymptotes

f (x) = \frac{x ^{2} - 2 x - 8}{x ^{2} - x - 12}

Vertical : x = - 3, Horizontal : y = 1

Solution steps

Vertical asymptotes of

\frac{x ^{2} - 2 x - 8}{x ^{2} - x - 12} : x = - 3

Horizontal Asymptotes of

\frac{x ^{2} - 2 x - 8}{x ^{2} - x - 12} : y = 1

Slant Asymptotes of

\frac{x ^{2} - 2 x - 8}{x ^{2} - x - 12} :

None

Vertical : x = - 3, Horizontal : y = 1

\frac{x ^{4} + 8}{x + 1}

4 x^{2} - 24 x - 30

4 x^{2} + 1 \cdot arctan (x)

y = \frac{x ^{2} + 3}{x - 1}

f (x) = \frac{( 5 x + 2 )}{x - 5}

What is the asymptotes of f(x)=(x^2-2x-8)/(x^2-x-12) ?
The asymptotes of f(x)=(x^2-2x-8)/(x^2-x-12) is Vertical: x=-3,Horizontal: y=1