What is the asymptotes of f(x)=(6x^2+1)/(2x^2+7x-4) ?

The asymptotes of f(x)=(6x^2+1)/(2x^2+7x-4) is Vertical: x=-4,x= 1/2 ,Horizontal: y=3

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asymptotes of f(x)=(6x^2+1)/(2x^2+7x-4)

asymptotes

f (x) = \frac{6 x ^{2} + 1}{2 x ^{2} + 7 x - 4}

Vertical : x = - 4, x = \frac{1}{2}, Horizontal : y = 3

Solution steps

Vertical asymptotes of

\frac{6 x ^{2} + 1}{2 x ^{2} + 7 x - 4} : x = - 4, x = \frac{1}{2}

Horizontal Asymptotes of

\frac{6 x ^{2} + 1}{2 x ^{2} + 7 x - 4} : y = 3

Slant Asymptotes of

\frac{6 x ^{2} + 1}{2 x ^{2} + 7 x - 4} :

None

Vertical : x = - 4, x = \frac{1}{2}, Horizontal : y = 3

\frac{( x + 4 ) ( x + 4 )}{( x + 1 ) ( x - 4 )}

f (x) = \frac{4}{( x + 2 ) ^{2}}

- \frac{1}{x ^{2}} cos (x) - 1

f (x) = \frac{1}{2} sec (2 x)

- \frac{8}{5 x + 4}

What is the asymptotes of f(x)=(6x^2+1)/(2x^2+7x-4) ?
The asymptotes of f(x)=(6x^2+1)/(2x^2+7x-4) is Vertical: x=-4,x= 1/2 ,Horizontal: y=3