What is the asymptotes of f(x)=((x^2+1))/(x^2-1) ?

The asymptotes of f(x)=((x^2+1))/(x^2-1) is Vertical: x=-1,x=1,Horizontal: y=1

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asymptotes of f(x)=((x^2+1))/(x^2-1)

asymptotes

f (x) = \frac{( x ^{2} + 1 )}{x ^{2} - 1}

Vertical : x = - 1, x = 1, Horizontal : y = 1

Solution steps

Vertical asymptotes of

\frac{x ^{2} + 1}{x ^{2} - 1} : x = - 1, x = 1

Horizontal Asymptotes of

\frac{x ^{2} + 1}{x ^{2} - 1} : y = 1

Slant Asymptotes of

\frac{x ^{2} + 1}{x ^{2} - 1} :

None

Vertical : x = - 1, x = 1, Horizontal : y = 1

f (x) = \frac{x ^{2} - 25}{x ^{2} - 8 x + 16}

f (x) = \frac{2 x - 3}{- x + 3}

f (x) = x^{2} - \frac{2}{x}

f (x) = \frac{6 x}{( x - 1 ) ^{2}}

f (x) = \frac{x ^{2} + 3 x - 7}{x - 1}

What is the asymptotes of f(x)=((x^2+1))/(x^2-1) ?
The asymptotes of f(x)=((x^2+1))/(x^2-1) is Vertical: x=-1,x=1,Horizontal: y=1