What is the asymptotes of f(x)= 1/((x-1)(x+1)) ?

The asymptotes of f(x)= 1/((x-1)(x+1)) is Vertical: x=-1,x=1,Horizontal: y=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

asymptotes of f(x)= 1/((x-1)(x+1))

asymptotes

f (x) = \frac{1}{( x - 1 ) ( x + 1 )}

Vertical : x = - 1, x = 1, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{1}{( x - 1 ) ( x + 1 )} : x = - 1, x = 1

Horizontal Asymptotes of

\frac{1}{( x - 1 ) ( x + 1 )} : y = 0

Slant Asymptotes of

\frac{1}{( x - 1 ) ( x + 1 )} :

None

Vertical : x = - 1, x = 1, Horizontal : y = 0

f (x) = \frac{x ^{3}}{3} - 9 x

f (x) = 2 x + sin (x)

\frac{4 x + 4}{x + 3}

\frac{x - 7}{x ^{2} - 16}

f (x) = \frac{1}{x} sin (\frac{x}{2})

What is the asymptotes of f(x)= 1/((x-1)(x+1)) ?
The asymptotes of f(x)= 1/((x-1)(x+1)) is Vertical: x=-1,x=1,Horizontal: y=0