What is the asymptotes of f(x)=(x^2+1)/(x^2-16) ?

The asymptotes of f(x)=(x^2+1)/(x^2-16) is Vertical: x=-4,x=4,Horizontal: y=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

asymptotes of f(x)=(x^2+1)/(x^2-16)

asymptotes

f (x) = \frac{x ^{2} + 1}{x ^{2} - 16}

Vertical : x = - 4, x = 4, Horizontal : y = 1

Solution steps

Vertical asymptotes of

\frac{x ^{2} + 1}{x ^{2} - 16} : x = - 4, x = 4

Horizontal Asymptotes of

\frac{x ^{2} + 1}{x ^{2} - 16} : y = 1

Slant Asymptotes of

\frac{x ^{2} + 1}{x ^{2} - 16} :

None

Vertical : x = - 4, x = 4, Horizontal : y = 1

\frac{2}{( x - 2 ) ^{3}}

\frac{4 x ^{2}}{12 x ^{2} - 6}

f (x) = x x^{2}

f (x) = 1 + lo g_{10} (x - 2)

g (x) = 4^{x - 3}

What is the asymptotes of f(x)=(x^2+1)/(x^2-16) ?
The asymptotes of f(x)=(x^2+1)/(x^2-16) is Vertical: x=-4,x=4,Horizontal: y=1