What is the asymptotes of f(x)=(x^2-x+5)/(3x^2-3x) ?

The asymptotes of f(x)=(x^2-x+5)/(3x^2-3x) is Vertical: x=0,x=1,Horizontal: y= 1/3

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asymptotes of f(x)=(x^2-x+5)/(3x^2-3x)

asymptotes

f (x) = \frac{x ^{2} - x + 5}{3 x ^{2} - 3 x}

Vertical : x = 0, x = 1, Horizontal : y = \frac{1}{3}

Solution steps

Vertical asymptotes of

\frac{x ^{2} - x + 5}{3 x ^{2} - 3 x} : x = 0, x = 1

Horizontal Asymptotes of

\frac{x ^{2} - x + 5}{3 x ^{2} - 3 x} : y = \frac{1}{3}

Slant Asymptotes of

\frac{x ^{2} - x + 5}{3 x ^{2} - 3 x} :

None

Vertical : x = 0, x = 1, Horizontal : y = \frac{1}{3}

f (x) = \frac{x ^{2} + 3 x - 9}{x - 9}

f (x) = \frac{( x ^{2} - 16 )}{x ^{2} + x - 12}

\frac{( 2 x - 7 )}{4 x + 15}

arctan (e^{- 4 x} - 1)

\frac{x ^{4} - 1}{x ^{3}}

What is the asymptotes of f(x)=(x^2-x+5)/(3x^2-3x) ?
The asymptotes of f(x)=(x^2-x+5)/(3x^2-3x) is Vertical: x=0,x=1,Horizontal: y= 1/3