What is the asymptotes of f(x)=(6x^2-5)/(1-3x) ?

The asymptotes of f(x)=(6x^2-5)/(1-3x) is Vertical: x= 1/3 ,Slant: y=-2x-2/3

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asymptotes of f(x)=(6x^2-5)/(1-3x)

asymptotes

f (x) = \frac{6 x ^{2} - 5}{1 - 3 x}

Vertical : x = \frac{1}{3}, Slant : y = - 2 x - \frac{2}{3}

Solution steps

Vertical asymptotes of

\frac{6 x ^{2} - 5}{1 - 3 x} : x = \frac{1}{3}

Horizontal Asymptotes of

\frac{6 x ^{2} - 5}{1 - 3 x} :

None

Slant Asymptotes of

\frac{6 x ^{2} - 5}{1 - 3 x} : y = - 2 x - \frac{2}{3}

Vertical : x = \frac{1}{3}, Slant : y = - 2 x - \frac{2}{3}

f (x) = \frac{3 x ^{3} - x ^{2}}{x ^{2} + 1}

7 x - 7

f (x) = \frac{2}{( x - 1 ) ^{2}}

\frac{- 2 x ^{2} + 4 x + 16}{x ^{2} - 5 x + 4}

f (x) = \frac{x - 3}{x ^{2} + 2 x - 15}

What is the asymptotes of f(x)=(6x^2-5)/(1-3x) ?
The asymptotes of f(x)=(6x^2-5)/(1-3x) is Vertical: x= 1/3 ,Slant: y=-2x-2/3