What is the asymptotes of (8x^3-7x)/(4x^2+5x) ?

The asymptotes of (8x^3-7x)/(4x^2+5x) is Vertical: x=-5/4 ,Slant: y=2x-5/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

asymptotes of (8x^3-7x)/(4x^2+5x)

asymptotes

\frac{8 x ^{3} - 7 x}{4 x ^{2} + 5 x}

Vertical : x = - \frac{5}{4}, Slant : y = 2 x - \frac{5}{2}

Solution steps

Vertical asymptotes of

\frac{8 x ^{3} - 7 x}{4 x ^{2} + 5 x} : x = - \frac{5}{4}

Horizontal Asymptotes of

\frac{8 x ^{3} - 7 x}{4 x ^{2} + 5 x} :

None

Slant Asymptotes of

\frac{8 x ^{3} - 7 x}{4 x ^{2} + 5 x} : y = 2 x - \frac{5}{2}

Vertical : x = - \frac{5}{4}, Slant : y = 2 x - \frac{5}{2}

f (x) = - \frac{26}{4 x}

f (x) = 8 lo g_{10} (x)

\frac{x ^{2}}{x ^{2} - 2}

f (x) = \frac{- 3 x}{x}

f (x) = \frac{- 6}{x - 7}

What is the asymptotes of (8x^3-7x)/(4x^2+5x) ?
The asymptotes of (8x^3-7x)/(4x^2+5x) is Vertical: x=-5/4 ,Slant: y=2x-5/2