What is the amplitude of-cos(3(θ-pi/6)) ?

The amplitude of-cos(3(θ-pi/6)) is 1

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amplitude of-cos(3(θ-pi/6))

amplitude

- cos (3 (θ - \frac{π}{6}))

1

Solution steps

f (x) = - cos (3 (θ - \frac{π}{6})), A = - 1

Therefore, the amplitude |A| is

1

1

x + 9 + (- 8 x - 4)

f (x) = - x + 4

f (x) = \frac{2 x}{7} + 4

f (x) = ∣ x ∣ + 2

f (x) = \frac{x ^{3} - x}{x}