What is the asymptotes of f(x)=1+7/x-3/(x^2) ?

The asymptotes of f(x)=1+7/x-3/(x^2) is Vertical: x=0,Horizontal: y=1

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asymptotes of f(x)=1+7/x-3/(x^2)

asymptotes

f (x) = 1 + \frac{7}{x} - \frac{3}{x ^{2}}

Vertical : x = 0, Horizontal : y = 1

Solution steps

Vertical asymptotes of

1 + \frac{7}{x} - \frac{3}{x ^{2}} : x = 0

Horizontal Asymptotes of

1 + \frac{7}{x} - \frac{3}{x ^{2}} : y = 1

Slant Asymptotes of

1 + \frac{7}{x} - \frac{3}{x ^{2}} :

None

Vertical : x = 0, Horizontal : y = 1

f (x) = \frac{x ^{2} - 8}{x - 3}

r (x) = \frac{6 x - 6}{x + 2}

\frac{2 x - 3}{3 x ^{2} - 3}

\frac{5 ( x + 2 )}{x ^{2} - x - 6}

\frac{4 x - 1}{x ^{2} - 16}

What is the asymptotes of f(x)=1+7/x-3/(x^2) ?
The asymptotes of f(x)=1+7/x-3/(x^2) is Vertical: x=0,Horizontal: y=1